Help! empirical formula problem!?

a food company is attempting to make synthetic starch. before the product is tested on laboratory animals, chemical analysis was done. a chemist burns 9.72g of the compound in O2, the products are 16.88 g CO2 and 9.76g H2O. determine the empirical formula of the compound, assuming it only contains C, H and O.

please help me answer this problem. or can you give the steps on how to solve it?

Answer:
first we find the amount of carbon in carbondioxide,12/44*16.88=4.60... hydrogen in water,2/18*9.76=1.0844 then oxygen we already have.Now for each element divide by its RMM to get a certain value.Then divide each of you answers by the smallest which in this case is 0.3836 the values you get finally should give you the formula.However what I get finally is a compound that can't possibly exist. But that doesnt matter wat matters is the answer! If you get something like C=1,H=3 and O=2 then we are on the same page,remember C can only mkae four bonds O = 2 would make it 5 so our answer cud be wrong .
O- 9.72/32gO2=0.303

CO2- 16.88g/44g= 0.383

9.76g/33g= 0.295

divide by the lowest answer 0.295

O- 0.303/ 0.295=1.02
CO2- 0.383/ 0.295= 1.29
H20- 0.295/ 0.295= 1

the empirical formula is CO2 O H2O

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