Please help me with this chemistry question?

In the following cell,
http://capa.chem.sunysb.edu/nan/concell_...


one of the compartments has a concentration of Ag+ = 1.00M.
For the next three questions, calculate the cell potential (V) at 25.0 C for the given concentrations of Ag+ in the other compartment

1) 1.10 M ?


2) 1.50 x 10−5 M ?


3) 1.00 M ?

Answer:
cell potential = 0.059 log C 1 / C2

C 1 > C2

1) cell potential = 0.059 log 1.10 / 1.00 =0.00244 V

2) cell potential = 0.059 log 1.00 / 1.50 10 -5= 0.285 V

3) cell potential = 0.059 log 1.00/1.00 = 0 V
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