what is the molarity of a solution that has 5.2g of NaCl in exactly 100mL of solution?
Answer:
c = n/V = m/MV (since n = m/M)
M(NaCl) = 23+35,5 =58,5 g/mol
c = 5,2g/(58,5g/mol)/0,1L= 0,89mol/L
Molarity (M) = moles/litre
NaCl: Mol.mass = 23 + 35.5 = 58.5g/mol.
5.2g ÷ 58.5g/mol. = 0.089moles/0.1L of solution.
0.089 ÷ 10 = 0.0089 Molarity.
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