How do you determine the boiling point of a liquid using the Clausius-Clapeyron equation?

I'm trying to find out the boiling point of a liquid using the Clausius-Clapeyron equation. I have no problem determining pressure or Hvap, but I think I'm rearranging it wrong when it comes to the temperature. Thanks for your help...

Answer:
If you have the Hvap then you have your answer (or as close as you may get). The Clausius-Clapeyron equation explains the boiling point (vaporization) as a difference between 2 points.

To determine the boiling point of an unknown use a different point of the equation:

ln[(P2)/(P1)] = [(∆Hvap)/R]*[(1/T1)-(1/T2)]
Use the ln p vs 1/T graph to find the ln p and 1/T values of a point on the straight line. Let these values be equal to ln p and 1/T . You have already determined ∆ Hvap in this experiment. T2 will then be the normal boiling point occuring at p2 = 1 atm..

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