3 MnO4{-} + 24 H{+} + 5 Fe = 3 Mn{2+} + 5 Fe{3+} + 12 H2O?

The half-reaction occuring at the anode in the balanced reaction shown above is what?

I can't figure this out can someone please help me thanks!

Answer:
It is not a half-reaction :
the half-reactions are
(MnO4- + 8 H+ + 5e- >> Mn2+ + 4H2O) x 3 >> reduction at cathode
(Fe >> Fe3+ + 3e-) x 5 >> oxidation at anode

Oxidation of Fe to Fe3+.

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3 MnO4{-} + 24 H{+} + 5 Fe = 3 Mn{2+} + 5 Fe{3+} + 12 H2O?

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