Hydrolysis - Chemistry?

How many moles of NaCN must be present in 2.6 L of solution in order to yield a solution whose pH = 10.00?

Answer:
First find the pKa of HCN. It is 9.2.

This is the salt of a weak acid and a strong base.
The formula for pH for these kinds of salts is
pH = 7 + 0.5 pKa + 0.5 log c
{Here c is the concentration of the solute}
10 = 7 + 0.5 * 9.2 + 0.5 log c
10 = 11.6 + 0.5 log c
-1.6 = log c
c = 2.512 * 10^-2 moles/L

2.512 moles are required for 1 L
So, the number of moles for 2.6 L = 6.5309*10^-2 moles

Thus we require 6.5309 * 10^-2 moles of NaCN

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