When 2.00 moles of H2O react, how many grams of NH3 are produced?

From the Balanced equation:
Mg3N2 + 6H2O-- 3Mg(OH)2 + 2NH3

Answer:
2H2O x 1mol H2O x 2NH3 x 1mol NH3 / 36g H2O x 6H2O x 34gNH3 = 5.44 NH3

5.44g of NH3 are produced
The ratio between H2O and NH3 is 6 : 2
6 (moles H2O) : 2 (moles NH3)= 2( moles H2O) : x
x = 0.667 moles NH3 produced
Molecular weight NH3 = 17 g/mol
0.667 mol x 17 g/mol = 11.3 g NH3 produced
the answer is that 2/3 moles of NH3 will be produced
according to mole concept
6 mole of h2o gives 2 mole of NH3
so,
2 mole wil give 2/6*2=.666 moles of NH3

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