I understand how to find the molar mass, but not if the solution is diluted. Can someone please explain how to do this problem and please provide the answer. Thank you.
Answer:
It will be .333M
First you find moles of KOH
.01L*(5mol/L)= .05 moles KOH
.05moles/.150L = .333 M KOH
multiply 5 M times (10 mL/150mL). The answer will be 5/15 M or 0.333 M
M1V1 (stock solution)= M2V2 (new solution)
5.00M* 10.0mL = M2 * 150.0 mL
After that, simply use what you've learned from algebra to get M2.
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