With the notation: Cu(s)/Cu2+(aq)//Aq+(aq)/A... which is true?
Cu is the cathode electrode
Electrons are flowing from Ag to Cu
None
Answer:
It'll be
2 Ag+(aq) + Cu(s) --> 2Ag(s) + Cu2+(aq)
Ag+(aq) + e- --> Ag E° = + 0.80 V
Cu2+(aq) + 2e- --> Cu E° = +0.34 V
From above, we know that Cu is more Electronegative than Ag.
So:
2Ag+(aq) + 2e- --> 2Ag E° = + 0.80 V
Cu(s) --> Cu2+ (aq) + 2e- E° = +0.34 V
---------- ------------- -------------- -------------- ------------- ------+
2 Ag+(aq) + Cu(s) --> 2Ag(s) + Cu2+(aq)
The cathode will be Ag
Electrones are flowing from Cu to Ag
We have to consider the E°
Ag+ 1 e- >> Ag E° = + 0.800 V
Cu2+ + 2e- >> Cu E° = +0.337 V
The reaction that occurs is
2 Ag+ + Cu >> 2Ag + Cu2+
Ag is the cathode
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