Sec 3 Chemical equation problem?

Ammonia reacts with acid to form ammonium salt. What volume of 2.00 mol dm^-3 of sulphuric acid will completely react with 240 cm³ of ammonia, measure at r.t.p

Please provide working steps..
Thanks.

Answer:
The equation is :
2 NH3 + H2SO4 >> (NH4)2SO4
At STP p = 1 atm and T = 273 K
V = 0.240 dm^3 = 0.240 L
pV = nRT
n = pV / RT
n = 1 x 0.240 / 0.0821 x 273 = 0.0107 moles NH3
The ratio between NH3 and H2SO4 is 2 : 1
2 : 1 = 0.0107 : x
x = 0.00536 moles H2SO4 needed
M = moles / V
v = moles / M = 0.00536 / 2.00 = 0.00268 L = 2.68 mL

Well work out the ratio of each substance in the reaction.
Then work out the moles of NH3 using its volume and conc (U MUST BE TOLD ABOUT THESE TWO)
Using the ratio determine the moles of H2SO4.
Using the moles and its conc, find out the volume of H2SO4.

to find out moles using conc and vol, use n=M x V
n= moles
M= concentration
V= volume

Use the Gas laws.

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Sec 3 Chemical equation problem?

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