What must the vapor pressure of Hg(g) be in order for this process to occur: Hg(l) <=> Hg(g)?

I'm guessing the answer is comparative, as in "greater than" or "less than" as opposed to an exact number.

Answer:
This process occurs all the time. Vapour pressure depends upon temperature, usually moving in the same direction. i.e. VP increases with increase in temp. At whatever temperature the vapour pressure equals the atmospheric pressure that is the boiling point of the liquid. That is the reason why boiling point is low at high altitudes where the atmospheric pressure is low.
0.00185 torr

There you go

*edit*

All better now.
The vapor pressure of the mercury needs to be greater than the atmospheric pressure.
The vapor pressure of the mercury needs to be greater than the atmospheric pressure, but mercury is a poison to environment. The vapor pressure of Hg(g) is in "greater than" or "less than" as opposed to an exact number. That I don`t know. I think you ask someone that know about it.

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