Determine the empirical formula of a compound containing 20.23 percent aluminum and 79.77 percent chlorine?
Answer:
Say you have 100 grams of the substance. That means 20.23 grams would be aluminium and 79.77 grams would be chlorine.
Convert those values to moles by dividing by the molar mass.
That yields:
0.749814678 moles Al
2.25021157 moles of Cl
divide 2.25 by .74 to figure out roughly the ratio of chlorine to aliuminum. it comes out very close to 3. That means the empirical formula is AlCl3. You have 3 times as much chlorine by quantity.
Divide 20.23 by 27 and 79.77 by 35.5, and you're nearly there!
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