Hydroquinone is an organic compound commonly used as a photographic developer. It has molar mass 110.1 g/mol and a composition of 65.45 percent C by mass, 5.45 percent H by mass, and 29.09 percent O by mass. Determine the molecular formula of hydroquinone. List elements in the formula in the same order as given in the problem statement, with subscripts immediately following the element symbol. If the subscript is 1, leave it off (1 is implied).
Answer:
The organic compound is Hydroquinone.
You are given it's molar mass=110.1 g/mol
IF you have one mol of this compound then you would have
C=65.45% of 110.1g
C=(65.45/100) x 110.1 g
= 72.06 g
AND you know one Carbon atom equal 12.00g therefore
C= 72.06/12 = 6
H=5.45% of 110.1g
H=(5.45/100) x 110.1 g
= 6.00 g
And you know one Hydrogen atom is 1.00g therefore
H= 6
O=29.09% of 110.1g
O=(29.09/100) x 110.1g
=32.0g
and each Oxygen atom is 16.0 g therefore
O= 32.0/16.0 =2
altogether you get the empirical formula of C6H6O2.
My answer is the same as "no_einstein" in the above.
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