What volume of hydrogen gas at STP is produced when 3.2 L of C6H6 (benzene) are produced at...?

What volume of hydrogen gas at STP is produced when 3.2 L of C6H6 (benzene) are produced at STP according to the following equation?
C6H14 —> C6H6 + H2 (need to balance)

Answer:
The balanced equation is
C6H14 ----> C6H6 + 4H2

So, the ratio of moles of C6H6:H2 is 1:4
So, when one mole of C6H6 is produced, correspondingly, 4 moles of H2 are produced.

We know that same number of moles occupy the same volume at constant conditions. So, we have the volume occupied by H2 = 4*3.2 = 12.8 L at STP

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