Calculate the hydroxide ion...?
Chemistry question... any work shown is very appreciated... Thanks!
Calculate the hydroxide ion (OH-) concentration in a 0.028 molar solution of nitric acid (HNO3).
Answer:
HNO3 --> H+ + NO3 - (100% dissociation)
so
[HNO3] = [H+] = 0.028 M
we know the K for water is
Kw = 10^-14
[H+] [OH-] = 10^-14
so
0.028 * [OH-] = 10^-14
we can conclude that hydroxid ion concentration will be:
► [OH-] = 3.57 x 10^-13
I hope this helpsCalculate the number of moles of:?
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Calculate the hydroxide ion (OH-) concentration in a 0.028 molar solution of nitric acid (HNO3).
Answer:
HNO3 --> H+ + NO3 - (100% dissociation)
so
[HNO3] = [H+] = 0.028 M
we know the K for water is
Kw = 10^-14
[H+] [OH-] = 10^-14
so
0.028 * [OH-] = 10^-14
we can conclude that hydroxid ion concentration will be:
► [OH-] = 3.57 x 10^-13
I hope this helps