Calculate volume of Carbon Dioxide?
Balance chemical equation is: C7H16 + 11 O ==> 7 CO2 + 8 H2O
Then I know I have to convert temperature to Kelvins : 300 + 273 = 573k
Then convert given mass to moles 50.0 * 10^3 g * 1 mol / 44.0 g CO2 = 1.136 mol
Then 1.136 * (and now I am lost) Any help would be appreciated.
Answer:
I think this is how you do it: I assume no legal resposnibility if you get an "F" on your homework! This program doesn't lend its self well to complex math equations I hope you can follow it.
Determine moles of gasoline (octane)
[50kg x 1000g/kg]/100g per mole octane = 500 moles
From the balanced equtation determine no of moles of CO2 that would be made
500 x 7 = 3500moles CO2
Convert 110kpa to Atm [look up conversion factor(s)]
Note convesion to lb/in2, then atm! I couldn't find direct conversion.
[110Kpa x 0.145lb/in2perKpa]/14.7 lb/in2/atm = 1.085 atm
Now use the ideal gas law to get volume in liters:
PV = nRT Make certain to use the right gas constant (R)! and T in kelvin!
1.085atm x [volume] = 3500 mol x 0.08205latm/K,mol x 573 K
Solve for volume:
volume = [3500 x 0.08205 x 573]/1.085
V = 151,600 liters
Your question did not specify what volume units; I did it in liters which is fairly common, if you need it in other units you can convert at your leisure. I hope this is correct, I haven't done this in a while.
Mr of C7H16 is (very helpfully) 100 exactly.
Moles C7H16 = 50,000/100 = 500.
Now multiply by 7 to the get the moles of CO2 = 7 x 500 = 3,500 (this is n for CO2).
Now use V = nRT/p to calculate the volume of CO2.
Over to you!
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