The equilibrium constant, Kc, for the reaction: SO3 + NO <--> NO2 + SO2?

was found to be 0.500 at a certain temperature. if 0.300 mol of SO3 and 0.300 mol of NO were placed in a 1.00 L container and allowed to react, what would be the equilibrium concentration of each gas?

Answer:
Initial concentration SO3 = 0.300 mol/ 1.00 L = 0.300 M

Initial concentrattion NO = 0.300 mol/ 1.00 L = 0.300 M

at equilibrium

[ SO3 ]= 0.300 - x

[ NO ] = 0.300 - x

[ NO2 ] = x

[ SO2 ] = x

K = [ NO2 ] [ SO2 ] / [ SO3 ] [ NO ]

K = 0.500 = (x)(x( / (0.300 - x)( 0.300 - x)

We can solve this equation by squaring both sides

sqr 0.500 =0.707

0.707 = x / 0.300 - x

x = 0.124 M

[SO3 ] = [NO ] =0.300 - 0.124 = 0.176 M

[ NO2 ] = [ SO2 ] = 0.124 M
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