Can you help me with this Chem problem?

A sample of tin having mass 5.506 g was oxidized and found to have combined with 1.484 g oxygen. Determine the empirical formula of this oxide of tin. List elements in the formula in the same order as given in the problem statement, with subscripts immediately following the element symbol. If the subscript is 1, leave it off (1 is implied).

Answer:
Dear Friend: Sn + O2= SnO2.
1.
5.506 + 1.484=7 grams.

1.484/7 X 100=21.2% oxygen.
2.Then if we have SnO2= 150.71 g

32 g. oxygen/150.71g = 21.2 %

1=2. Its SnO2.
1) Divide the mass of tine by its atomic weight to get number of moles of tin.
2) Divide the mass of oxygen by the atomic weight of oxygen to get the number of moles of oxygen.
3) You know the number of moles of Sn and of O will be in some simple ratio. Take the smaller number of the two and use it to divide both. Fiddle around with the results, multiplying by small numbers like 2, 3, etc. until you get both numbers for Sn and O pretty close to "whole" numbers. That's your answer.

4) Or cheat. You know that the common oxidation states for Sn are +2 and +4, giving formulas of SnO and SnO2 respectively. See which one fits your number of moles for Sn. and O.
i think SnO is correct. Cuz:

5.506 / 119(mr of Sn)=0.046268907

1.489/(16 x 2)= 0.046375

0.046375/0.046268907 =1.002292953
0.046375/0.046375 = 1

so empirical formula =SnO

The answers post by the user, for information only, FunQA.com does not guarantee the right.



More Questions and Answers:
  • Chemistry help plz! About Molecular Formula!?
  • What is the percent yield if 56.9 g of WO3 yields 41.4 g of tungsten?
  • Calculate the mass of 4.56 moles of helium.?
  • Suggest e possible reasons for the differences between the measured height n calculated ht in purge dip system
  • Chemistry oxidation number question?
  • Constant question?
  • What is the purpose of homogenizing the onion?
  • 195-1-Chemistry-4.html
  • 3/3 Challenge!!!1 for chem. wiz only!?