What volume of carbon momoxide gas at STP is produced form 6.14g calcuim phoshate and 8.24g silicon dioxide..?
2Ca3(PO4)2+6SiO2+10C->P4 + 6CaSiO3+10CO already balanced?
Answer:
Molar mass Ca3(PO4)2 = 310 g/mol
moles Ca3(PO4)2 = 6.14 / 310 = 0.0198
Molar mass SiO2 = 60.1 g/mol
moles SiO2 = 8.24 / 60.1 = 0.137
the ratio between Ca3(PO4)2 and SiO2 is 2 : 6
2 : 6 = 0.0198 : x
x = 0.0594 moles SiO2 needed ( we have 0.137 moles ) so SiO2 is in excess and Ca3(PO4)2 is the limiting reactant
the ratio between Ca3(PO4)2 (limiting reactant ) and CO is 2 : 10
2 : 10 = 0.0198 : x
x = 0.099 moles CO produced
at STP p =1 atm and T = 273 K
V = nRT / p = 0.099 x 0.0821 x 273 / 1 = 2.22 L of CO
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