Concentration of Ions?

I need some help. I need to calculate the concentration of iodide ions in a saturated solution of lead iodide (Ksp=1.39 x 10 to the -8 power). Thank you.

Answer:
The equilibrium is
PbI2 (s) <---> Pb2+ + 2I-
Ksp = [Pb2+] [ I-]^2
Let x = moles/l of PbI2 that dissolve. We get x moles/L Pb2+ and 2x moles/L I-
Ksp = 1.39 x 10^-8 = (x) (2x)^2 = 4x^3
x = 0.00151 M = [Pb2+]
2x = 0.00303 M = [I-]

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