How do I calculate theoretical yield here?
I am starting with 1.61g of p-toluidine
Since this has excess reagents, there is a 1:1 molar ratio in the synthesis right? And if that is the case would I just convert to moles of p-toluidine, multiply by 1:1 ratio (which is the same of course) then multiply by molecular weight of benzocaine to get grams theoretical?
Answer:
First : we convert g in moles
Molar mass p-toluidine = 107.17 g/mol
1.61 g / 107.17 = 0.0150 moles of p-toluidine
the ratio is 1:1 so we wuold get 0.0150 moles of benzocaine
Molar mass benzocaine = 165.189 g/mol
0.0150 mol x 165.189 g/mol = 2.48 g formed
I don't think you multiply it by 1:1 ratio.
I'm guessing you'll need the formula mass of p-toluidine.
My chemistry is a bit fuzzy since school ended. But good luck, Theoretical Yield really messed up my thinking. Lol.
First calculate the number of moles in 1.61g of p-toluidine (ie. 1.61g/MW of p-toluidine). The theoretical yield assumes the % yield in each step of the sequence is 100%. If that is true then the number of moles of your final product (benzocaine) should equal the number of moles of p-toluidine. So to get the final grams of benzocaine multiply the number of moles of p-toluidine and therefore benzocaine by benzocaine's moleculat weight. This will give you the number of theoretical grams. All in all your proposal on how to do the calculation is the same as I have described to you. Good luck and I hope this helps.
Theoretical Yield
this is how much product will be synthesized in ideal conditions.
To determine theoretical yield, multiply the amount of moles of the limiting reagent by the ratio of the limiting reagent and the synthesized product and by the molecular weight of the product.
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