Assume the reaction of 42.56 g of Fe in the following reaction to determine the other quantities...?

3Fe + 2O2 -> 1Fe3O4

moles of Fe reacting = how many mol?
moles of O2 required =how many mol?
moles of Fe3O4 formed =how many mol?
mass of Fe3O4 formed =how many g?

thanks!

Answer:
42.56 g / 55.847 = 0.816 mol Fe reacting

3 : 2 = 0.816 : x x = 0.544 mol O2 required

3 : 1 = 0.816 : x x = 0.272 mol Fe3O4 formed

0.272 mol x 231.54 g/mol = 63 g Fe3O4 formed
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