Solve the inequality?
Answer:
you should use some brackets...
is it (2x/6)-x<x or 2x/(6-x)<x
i assume it's the latter since the first one is nonsense...
2x/(6-x)<x
2/(6-x)<1
2<6-x
-4<-x or x<4
2x/6-x < x
so
2x< x(6-x)
2x<6x-x square
(x square)- 4x=0
x(x-4)=0
X=0 or X=4.
so the answer is 0<x<4
whereby x is 1,2 or 3 only.
x =/ 6
2x/(6-x)-x<0 2x/(6-x)-x(6-x)/6-x<0
2x-6x+x^2/(6-x)<0 x^2-4x/6-x<0
x(x-4)/6-x<0 x(x-4)(6-x)<0 0<x<4 or x>6
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