How many grams of MgCO3 contain 24.0 grams of Oxygen when the molar mass og MgCO3 is 84.3 grams?
I need to know the answer to this.. complete with the steps so I know how to do this kind of problem in the future.
Answer:
First, find the mass of oxygen in one mole of MgCO3. There are 3 oxygen atoms in each mole, and the atomic mass of oxygen is 16 g/mole. 3*16 = 48, so there are 48 grams of oxygen in one mole of MgCO3.
You know that the molar mass of MgCO3 is 84.3g.
From that, you can set up a proportion:
48g O/84.3g MgCO3 = 24g O/ Xg MgCO3. Solve for X by taking 24 and dividing by (48/84.3). You then get 42.15g MgCO3. That is your answer.
ok, first you need to know how many moles 24.0 grams of oxygen is, so you divide the 24.0 by the molar mass of oxygen, 8 g/mol. this gives you an answer of three moles of oxygen in your sample. so this is an easy problem, because you can tell by the chemical formula that every mole of magnesium carbonate has three moles of oxygen involved in it. if it's not a nice number, just divide the moles of oxygen by the moles of oxygen in the chemical formula and you'll have your moles of MgCO3. multiply the moles of MgCO3 by the molar mass, and you have your grams of MgCO3, which in your case is 84.3 grams.
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Answer:
First, find the mass of oxygen in one mole of MgCO3. There are 3 oxygen atoms in each mole, and the atomic mass of oxygen is 16 g/mole. 3*16 = 48, so there are 48 grams of oxygen in one mole of MgCO3.
You know that the molar mass of MgCO3 is 84.3g.
From that, you can set up a proportion:
48g O/84.3g MgCO3 = 24g O/ Xg MgCO3. Solve for X by taking 24 and dividing by (48/84.3). You then get 42.15g MgCO3. That is your answer.
ok, first you need to know how many moles 24.0 grams of oxygen is, so you divide the 24.0 by the molar mass of oxygen, 8 g/mol. this gives you an answer of three moles of oxygen in your sample. so this is an easy problem, because you can tell by the chemical formula that every mole of magnesium carbonate has three moles of oxygen involved in it. if it's not a nice number, just divide the moles of oxygen by the moles of oxygen in the chemical formula and you'll have your moles of MgCO3. multiply the moles of MgCO3 by the molar mass, and you have your grams of MgCO3, which in your case is 84.3 grams.
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