What mass of magnesium chloride is needed to react with 145g of silver nitrate according to this reaction?
Answer:
Mole ratio of MgCl2 and AgNO3 is 1:2
Number of moles in 145g of AgNO3 = 145/170 = 0.852 moles
Remember the mole ratio? Hence half as much moles of MgCl2 is required, so 0.852/2 = 0.426 moles.
Then conversion back into mass - using n = mMr, 0.426 x (24 + 71) = 40.5g of MgCl2 required.
The answers post by the user, for information only, FunQA.com does not guarantee the right.
More Questions and Answers: