What mass of magnesium chloride is needed to react with 145g of silver nitrate according to this reaction?

MgCl2(aq)+2AgNO3(aq)--->Mg(NO3...

Answer:
Mole ratio of MgCl2 and AgNO3 is 1:2

Number of moles in 145g of AgNO3 = 145/170 = 0.852 moles

Remember the mole ratio? Hence half as much moles of MgCl2 is required, so 0.852/2 = 0.426 moles.

Then conversion back into mass - using n = mMr, 0.426 x (24 + 71) = 40.5g of MgCl2 required.

The answers post by the user, for information only, FunQA.com does not guarantee the right.



More Questions and Answers:
  • Question about acid names?
  • Chemistry question?
  • Test for hydrogen gas?
  • What chemical can kill a cat?
  • What is difference between atomic mass & equivalent mass?
  • The ratio of the lengths of corresponding parts in two similar solids is 4:1?
  • What is o3?
  • Science Experiment Research Assistance?
  • A catalyst speeds up a chemical reaction as a result of which of the following?