I need help with these 2 chemistry questions?
2) how many moles of oxygen are in 3.70 moles of NaClO4?
Answer:
1) I'm going to use the empirical route.
Firstly divide all the percentages by the atomic masses of the elements:
C: 40/12 = 3.33
H: 6.7/1 = 6.7
O(I assume?): 53.3/16 = 3.33
Now I divide through by the lowest number, 3.33 to give me the molar ratios: C:1, H:2, O:1
Hence the empirical formula is CH2O
Now we calculate the molecular mass of the empirical = 12+2+16 = 30, and we divide the given molecular mass by this to find the factor needed to convert the empirical to molecular: 180.15/30 = 6.00
So we multiple the empirical by 6: 6 x CH2O = C6H12O6 (wow it's glucose!)
2) 4 moles of oxygen in NaClO4, hence there will be four times as much oxygen per mole of NaClO4 = 4 x 3.7 = 14.8 moles.
I'm not gonna do your homework
I will teach you alittle though, sounds your teacher didn't
Moles of something is like Avogadro's number of those, atoms, or molecules 6.023 x 10^23
for Hydrogen , since molecular weight is 1, one mole weighs one gram
look at the periodic table, think in term of grams per mole
ask your teacher also maybe
40% of 180 is 72. There are 6 carbon atoms.
6.7% of 180 is 12. There are 12 hydrogen atoms.
53.3% of 180 is 95. But we have already had carbon. Could it be oxygen instead of carbon? I suspect that you're dealing with glucose, c6h1206, which has that distribution of C, H, and O.
You produce 4 moles of atomic oxygen, or 2 moles of molecular oxygen when you break up a mole of NaCl04. Thus, the answer is 7.4 moles if the oxygen is released into the atmosphere, or 14.8 moles if the oxygen is being used in another reaction.
1) first we have to find the empirical formula. first u need to divide each percentage by the atomic weight of the element.
40% C / 12 = 3.33
6.7% H / 1 = 6.7
53.3% O /16 = 3.33
now divide every thing by the smallest number 3.33.
3.33 C / 3.33 = 1 C
6.7 H / 3.33 = 2.0 H
3.33 O / 3.33 = 1 O
so the empirical formula is CH2O.
next step is to find the molecular weight of the empirical formula and to figure out how many times more the MM is that the empirical.
the empirical weighs 12 + 2 + 16 = 30. is the molar mass is 180, the it is 6 times the empirical formula, so the molecular formula is C6H12O6.
2) well there are 4 atoms of O in 1 molecule of NaClO4, so there 4 times as many moles = 3.7 x 4 = 14.8 moles.
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