Calculate the ph of a solution formed by mixing 10ml of 0.1M HBr with 20ml of 0.2M HCl.
Answer:
30 mL with an [H+] of .5/3 M or .167 M
pH = -log [H+] = -log [.167] = .778
They are both strong acids.
Total volume 30ml (= 0.030 litres).
Total acid moles = 10/1000 x 0.1 + 20/1000 x 0.2.
Now divide the total moles by the total volume to get [H+], and then take the negative logarithm in the normal way.
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