Bromomethane reactions?

Write the equation for the formation of bromomethane from methane.
Is this correct?

CH4 + Br. ------> CH3. + HBr
CH3 + Br2 ------> CH3Br + Br.

The . stands for free radicals

(i) Write an equation for the reaction of dibromomethane with bromine to form tribromomethane

(ii) Draw out the mechanism for the reaction between tribromomethane and bromine

Answer:
Yes, but you left out the important initiation step:

Br-Br ----> 2 Br* Initiation

CH4 + Br* -----> CH3* + HBr Propagation

CH3* + Br* -----> CH3Br Propagation

Br* + Br* -----> Br2 Termination


i) Then follow the same logic as above

Br-Br ------> 2 Br* Initiation

Br* + CH2Br2 ------> CHBr2* + HBR Propagation

CHBr2* + Br* ------> CHBr3 Propagation

Br* + Br* -------> Br2 Termination


ii) Same as (i) except for propagation steps

CHBr3 + Br* -------> CBr3* + HBr

CBr3* + Br* ---------> CBr4
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