Aluminum reacts with sulfuric acid, which is the automobile batteries. if 20.0 grams of Al is placed into a so
Answer:
2Al + 3H2SO4 ==> Al2(SO4)3 + 3H2
=> 3 mols of H2 is produced from 2 mols of Al
=> 3 * 2.016 gm of H2 is produced from 2 * 26.982 gm Al
=> from 20 gm of Al , 3 * 2.016 * 20 / 2 * 26.982 gm H2 will be evolved
= 2.241 gm of H2 will be evolved.
All problems of this sort are solved the same way: construct the balanced equation, determine the molecular weights, determine the number of moles of the reactants, determine the limiting reactant, and figure out how much product is produced in moles, and then in grams. I will give you the equation:
2 Al + 3 H2SO4 -> Al2(SO4)3 + 3 H2.
2 Al + 3 H2SO4 -> Al2(SO4)3 + 3 H2
20 g will take up 20*3*98/54 = 33.06 g of H2SO4
So, gms of H2 = 20*3*2/54 = 2.22 g
Just FYI -- automotive batteries do NOT use aluminum. They are lead-acid batteries, because that reaction is reversible. The Aluminum-sulfuric acid reaction is **not** reversible, and is too vigorous to be safe in an auto.
But the others are correct -- the reaction you are looking for is:
2 Al + 3 H2SO4 == Al2(SO4)3 + 3 H2
So figure out how many moles of AL and how many moles of H2SO4 you have, determine the limiting reagent, and then figure out how much hydrogen is produced. Easy.
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