When 71.43 mL of .855 molar nitric acid is diluted with 20.57 mL of water the molarity of the nitric acid.?

Becomes what?

Answer:
0.855 M means 0.855 moles solute in 1 liter (1000 mL) of solution
moles HNO3 in 71.43 mL = 71.43 x 0.855 / 1000 = 0.06107
Total volume = 71.43 + 20.57 = 92.00 mL = 0.09200 L
M = 0.06107 / 0.09200 L = 0.6638

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