What is the percent composition of Li2O?

Answer:
Molecular mass Li2O = 29.88 g / mol

15.9994 : 29.88 = x : 100

x = 53.5 % O

100 - 53.5 = 46.5 % Li

Depends on the periodic table you use according to mine...

Li2: 13.882 g/mole
O: 15.9994 g/mole

Li: 13.882 + O: 15.9994 = Li2O: 29.881

Li2O: 29.881

so...

Li2: 13.882/29.881 x 100% = 46.457%
O: 15.9994/29.881 x 100% = 53.543%

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