Equilibrium state?

in terms of...

change in observable properties
and
energy and entropy state

Answer:
At equilibrium any reaction seems to have stopped, so there is no observable change - even though both the forward reaction and the backward reaction are still going ahead at full speed.

Delta G = 0 at equilibrium, so any enthalpy change has to be exactly cancelled out by any entropy change multiplied by the temperature:

Delta G = delta H - (T x Delta S).
Data required.
Delta G = 0 for equilibrium so it follows that

delta H = T* delta S

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