If the gas is heated to a temperture of 116 dgreees C and expandd to a volume of 4.49L, what is its final presure in mmHg
Answer:
p1 = 855 / 760 = 1.12 atm
T1 = 39 + 273 = 312 K
T2 = 116 + 273 = 389 K
p1V1 = nRT1 >> p1V1 / T1 = nR
p2V2 = nRT2 >> p2V2/ T2 = nR
p1V1 / T1 = p2V2 / T2
1.12 x 2.45 / 312 = p2 x 4.49 / 389
0.00879 = p2 x 0.0115
p2 = 0.761 atm
0.761 x 760 = 578.8 mm Hg
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