What is the ionic equation for the reaction between sulfuric acid and sodium hydroxide?
Answer:
H2SO4 + 2NaOH --> Na2SO4 + 2H2O
2H+ + SO42- + 2Na+ + 2OH- --> 2Na+ + SO42- + 2H+ + 2OH-
After terminating all the spectators ions (ions that occur at both sides of the stoichiometry equation-that is sodium ion, Na+ and sulphate ion, SO42-, ), we'll get:
H+ + OH- --> H2O
H2SO4+2NaOH-----> Na2SO4+2H2O
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