The burning of ethane produceds both Co2 and H2O. If 200mL of C02 is produced at 20 degrees celcius and...
Answer:
The balanced equation is
2 C2H6 + 7 O2 >> 4 CO2 + 6 H2O
we use
pV = nRT
n = pV / RT
p = 750 / 760 = 0.987 atm
V = 200 mL = 0.200 L
T = 20 + 273 = 293 K
n = 0.987 x 0.200 / 0.0821 x 293 = 0.00822 moles of CO2
the ratio between CO2 and H2O is 4 : 6
4 : 6 = 0.00822 : x
x = 0.0123 moles water vapor produced
V = nRT / p
p = 790 / 760 = 1.04 atm
T = 24 + 273 = 297
V = 0.0123 x 0.0821 x 297 / 1.04 = 0.288 L = 288 mL of water vapor produced
Tommy
I checked Dr A's answer and it's correct. Don't know why someone gave him a thumbs down.
The only thing I would have done differently is to use
62.3637 L x Torr / mole x K for the value of R instead of converting to atmospheres. your call though...
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