What is the mass percentage of the aqueous solution of 6 mol/l sulphuric acid? (density of solution is 1.34g/ml), (formula mass of H2SO4 is 98.1)
The answer is 43.9% but how do we work this out??
Thanks in advance for your help
Answer:
x g/L / 98.1 = 6 mol/L
x g/L = 588.6 g/L
1340 g/L x mass% /100 = 588.6 g/L
mass % = 43.9 %
H2SO4 is 6mol/l or 6*98.1 =588.6 g/l;
The density of solution =1.34 g/ml; or 1340g/l
Therefore for mass percentage we have to divide it by 1340;
Mass percentage of H2SO4 = (588.6/1340)*100;
= 43.9 %
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