How do i know when to use grams or milligrams in calculations?
"What mass of silver nitrate is required to be weighed out to prepare 250 mL of a 0.125M solution?"
This is my understanding so far:
mass of solute = concentration x volume of solution
= 0.125 x 250
= 31.25??
I'm hoping that I've calcaulated it right, but what I'm really stuck on is which unit I should use. would it be in g or mg?
Many thanks!
Answer:
It is not right because
Molarity = moles solute / L solution
250 mL = 0.250 L
moles of solute = 0.125 x 0.250 = 0.0312
Molar mass AgNO3 = 169.87 g/mol
0.0312 mol x 169.87 g / mol = 5.30 g of AgNO3 needed
Note : look at significant figures : there are 3 significant figures so in any case 31.25 is not right because it has 4 significant figures
i think its mg.
when concentration is in molar the mass is in grams in relation to litre.
here,it is grams*millilitre=milligrams
so th unit is mg.
31.468 grams of silver nitrate
250mL = 250cc's
250 X .125 =31.25cc's
31.25 cc's X 1.007(density of silver nitrate) = 31.468 grams
I hoped this helped. :)
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This is my understanding so far:
mass of solute = concentration x volume of solution
= 0.125 x 250
= 31.25??
I'm hoping that I've calcaulated it right, but what I'm really stuck on is which unit I should use. would it be in g or mg?
Many thanks!
Answer:
It is not right because
Molarity = moles solute / L solution
250 mL = 0.250 L
moles of solute = 0.125 x 0.250 = 0.0312
Molar mass AgNO3 = 169.87 g/mol
0.0312 mol x 169.87 g / mol = 5.30 g of AgNO3 needed
Note : look at significant figures : there are 3 significant figures so in any case 31.25 is not right because it has 4 significant figures
i think its mg.
when concentration is in molar the mass is in grams in relation to litre.
here,it is grams*millilitre=milligrams
so th unit is mg.
31.468 grams of silver nitrate
250mL = 250cc's
250 X .125 =31.25cc's
31.25 cc's X 1.007(density of silver nitrate) = 31.468 grams
I hoped this helped. :)
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