What is the [H=] in 0.200 M HCLO? Ka= 2.88x 10 negative 8th power?

Answer:
Let us say the [H+] = x

then: Ka = [H+][ClO-]/[HClO] = 2.88*10^-8 = x^2/(0.2-x)

so x^2 + 2.88*10^-8 - 5.76*10^-9 = 0

solving the quadratic x = 7.58*10^-5 M = [H+]

the other root is negative

CONSIDERING 1 MOL OF HOCL INITIALLY
HCLO = H+ + OCL-
1 0 0 initially
1-x x x at eqb

hence x^2/(1-x)=Ka
solving we get x=____
[H] = x*.2 M

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