Calculate the solubility of AgCl in 0.20 M AgNO3 solution. Ksp of AgCl is 1 x 10-10.?
Answer:
AgNO3 is a strong electrolyte. It will dissociate completely and thus we have a concentration of Ag+ ions of 0.20 M in the solution before AgCl is added.
Now, let the solubility of AgCl in the solution be x
The ions supplied are the Ag+ and the Cl- ion. Due to the common ion effect of the Ag+ ion, we have a lesser solubility than in pure water. The Cl- concentration in the solution = x.
The concentration of Ag+ = 0.2+x
Here the solubility of AgCl is very small so x<<0.2. So, x+0.2 == 0.2
Substitute in the Ksp formula we have
[0.2][x]=1*10^-10
x = 5*10^-10
The solubility is thus 5*10^-10 moles/liter
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