If the Ksp for PbI2 is 3.1 x 10-7, will precipitation of PbI2 occur when 10mL of 1.0 x 10-5M Pb(NO3)2 is?

mixed with 10mL of 1.0 x 10-2M KI?

Answer:
Lead nitrate and potassium iodide are both strong electrolytes. So we have them completely dissociating.

[Pb] = [Pb(NO3)2] = 10^-5
[I] = [KI]=10^-2

Q = [Pb][I][I] = 10^-5*10^-2*101^-2 = 10^-9

This is the reaction quotient for PbI2. This is less than the Ksp of PbI2 at this temperature. So, we have no precipitation taking place.

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If the Ksp for PbI2 is 3.1 x 10-7, will precipitation of PbI2 occur when 10mL of 1.0 x 10-5M Pb(NO3)2 is?

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