How Calculate n(H2) obtained from 1.000 gram of Al. Also, calculate n(H2) obtained from 1.000 gram of Zn.?
Answer:
Look at the reaction involved in each case
-> For Aluminum :
Al + 3HCl -----> AlCl3 + 1.5 H2
Thus each atom of aluminium releases 1.5 moles of H2 gas. So, 1 mole of aluminum releases 1.5 moles of H2 gas. The number of moles of Aluminum involved = 1/27 moles
So the number of H2 released = 1.5/27 = 1/18 moles = 0.0555556 moles
->For zinc
Zn + 2HCl ----> ZnCl2 + H2
Thus each atom releases 1 molecule of H2. The number of moles of Zn involved = 1/65.4 = 0.0153 moles
So, the number of moles of H2 = 0.0153 moles
n(H2) in case of Aluminum = 0.055556
n(H2) in case of Zinc = 0.0153
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