Muriatic acid is often used to remove rust. A solution of muriatic acid, HCl, reacts with Fe(2)O(3) depositson industrial equipment. how many liters of 5.50 M would be nedded to react completely with 439 g Fe(2)O(3)?
Answer:
Fe2O3 +6 HCl >>2 FeCl3 +3 H2O
molar mass Fe2O3 = 159.7 g/mol
439 g / 159.7 = 2.75 moles Fe2O3
the ratio between Fe2O3 and HCl is 1 : 6
1 : 6 = 2.75 : x
x = 16.49 moles HCl needed
M = moles/L
L =moles/ M = 16.49 / 5.50 = 3.00 L HCl
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