Molar concentration from titration value?
Calculate the molar concentration of a thiosulfate solution from the following information: a 25 mL aliquot of 0.0195 M KIO3 (potassium iodate) solution is added to a flask containing 2 g of KI and 10 mL of 0.5 M H2SO4. The resulting solution is titrated to a starch endpoint with 34.81 mL of the thiosulfate solution.
Answer:
The equations are as follows:
IO3- +5I- +6H+ >> 3I2 +3H20
3I2+6S2O3- >>6I- + 3S4O6-
0.025L x 0.0195Moles IO3- == 4.9E-4moles IO3-
.....1Liter
4.9E-4Moles IO3-x 6molesS2O3- ==2.9E-3MolesS2O3-
..... .... 1mole IO3-
(2.9E-3molesS2O3-)/(0.03481L)= 8.3E-2 M
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Answer:
The equations are as follows:
IO3- +5I- +6H+ >> 3I2 +3H20
3I2+6S2O3- >>6I- + 3S4O6-
0.025L x 0.0195Moles IO3- == 4.9E-4moles IO3-
.....1Liter
4.9E-4Moles IO3-x 6molesS2O3- ==2.9E-3MolesS2O3-
..... .... 1mole IO3-
(2.9E-3molesS2O3-)/(0.03481L)= 8.3E-2 M
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