What is the pH of a buffer solution...?

that is 0.211 M in lactic acid and .111M in sodium lactate? The Ka of lactic is 1.37x10^-4 an someone just show me how to set this up thanks

Answer:
Ka= [H][A]/[HA]

1.37x10^-4=[x][.111]/[.211]
x=0.000260423 M H+

pH=-log [H]

so
pH=-log[0.000260423]
pH=3.584

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