If you are working a problem that asks you to find the solubility of Cr(OH)3 in water and you assign variables
b. 2
c. 3
d. 4
Answer:
The equilibrium is
Cr(OH)3 <--> Cr3+ + 3OH-
and the requirement for this equilibrium is that
Ksp = [Cr3+] [ OH-]^3 = 6.3 x 10^ -31
Let x = moles / L of Cr(OH)3 that dissolve : we have x moles/L of Cr3+ and 3x moles /L of OH-
6.3 x 10^-31 = (x) ( 3x)^3 = 27x^4
x = 1.2 x 10^-8 M = molar solubility
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