Help me please??

The molarity of an aqueous solution containing 75.3 g of glucose (C6H12O6) in 35.5 mL of solution is __________.

Answer:
Molarity = no. of moles of solute/ volume of solution in liters
no. of moles = weight/molecular mass.
molecular mass of glucose = 180

Molarity = weight / (molecular mass)(volume in liters)

molarity = 75.3 / (180)(0.0355)
molarity = 11.78 mol/lit

there u go, just remember the formulas.
figure out what the molecular weight of your molecule is.
Divide that by the actual weight (75.3g), now you've got how many moles you have. Molarity is just moles divided by volume.

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