Chemistry question???

An aqueous ethanol solution (400 mL) was diluted to 4.00 L, giving a concentration of 0.0400 M. The concentration of the original solution was __________ M

Answer:
use the formula c1v1 = c2v2

where
c1 is the concentration of the original solution
v1 is the volume of the original solution ==> 400mL = 0.4L

c2 is the concentration of the final solution ==> 0.0400M
v2 is the volume of the final solution ==> 4.00L

substituting these values into the formula you find that

c1 x 0.4 = 0.0400 x 4. 00

0.4c1 = 0.16

c1 = 0.16 / 0.4 = 0.4M

therefore the concentration of the original solution was 0.4M.
you have 0.0400 moles in 1 liter. in 4 liters, you have 0.16 moles. These 0.16 moles came from 400 ml of original solution. so if from the original solution 400 ml have 0.16 moles than 1000 ml have 0.4 moles. ANSWER: 0.4 M.
Find the number of moles in the 4 liter solution. You know it is .04 Molar.
Use that number of moles and now consider only .4 L solution.
Use the M1V1 = M2V2 equation. Make sure you use the same units throughout.

(0.400 L)( x ) = (0.0400 M)(4.00 L)

Therefore, x = 0.4 M
0.4 M

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