Find the mole fraction of the FeCl2 in the following solution:?
150 g C6H23O 42.7 g KI 320 g FeCl2 50 g H2O
Answer:
1...C6H23O Mol.mass = 72 + 23 + 16 = 111.
2...KI Mol. Mass = 39 + 127 = 166
3...FeCl2 Mol.mass = 56 + 71 = 127
4...H2O Mol. mass = 18
No.of moles of each = Mass/Mol.mass
1...150/111 = 1.351 moles.
2... 42.7/166 = 0.257 moles.
3... 320/127 = 2.520 moles
4... 50/18 = 2.778 moles.
Total moles = 6.906
Mole fraction of FeCl2 = Moles/Total moles.
= 2.520/6.906
= 0.365 = 36.5% FeCl2
(1 + 2 + 4 = 63.5% (calculated)).
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