At STP, 12.69g of noble gas occupies 14.09L. What is the identity of the noble gas?
Answer:
22.40 L·mol−1 / 14.09L * 12.69 g = 20.17 g·mol−1
Neon data: Standard atomic weight 20.1797(6) g·mol−1
So the answer is • Ne •
Use the ideal gas law (PV=nRT) to figure it out! You can find n which will tell you what gas it is. (NOTE: STP means standard temperature and pressure)
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