In terms of enthalpy, how would this reaction proceed (2)H20 (l) + electrical energy --> (2) H2 (g) + O2 (g)
2 H2O (l) + electrical energy → 2 H2 (g) + O2 (g)
Using your knowledge of (delta)H and (delta)S, explain why this reaction would proceed as written.
Answer:
If electrical energy is added, you are increasing deltaS which is the change in entropy of energy differences. delta H is the change in heat energy. :) If you start off with energy in the reactants, most likely it will be a non-spontaneous reaction because spontaneous reactions occur with the help of energy or
a release of energy. Hope this helps :)
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